From: "Carl Gehr" <os2-wireless_users@2rosenthals.com>
To: "OS/2 Wireless Users Mailing List" <os2-wireless_users@2rosenthals.com>
Date: Fri, 21 Apr 2006 14:33:37 -0400 (EDT)
Reply-To: "Carl Gehr" <Carl.Gehr@attglobal.net>
Priority: Normal
In-Reply-To: <list-71522@2rosenthals.com>
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Subject: Re: [OS2Wireless]Wireless dialup
Message-Id: <20060421183341.MCIO4722.gx6.fuse.net@localhost>

I hope you get an answer to this!

I also have Cingular via a Treo 650.  It SHOULD be able to work as you
describe.  I have also been reluctant to contact Cingular, expecting
the same responses you mentioned.

Carl

On Fri, 21 Apr 2006 11:02:00 -0700, Ray Davison wrote:

>My laptop has both wired and built-in wireless connections.  They both 
>work under OS/2.  Sometimes neither is available on the road.  I have a 
>cell phone with Cingular service.  They have a Windows application 
>called Cingular Communication Manager.  Under Win I can connect the 
>phone as a modem, and Comm Mgr will dial into Cingular and connect me to 
>the WEB.  I have the choice of paying for time or traffic volume; I 
>chose time.
>
>I would rather not connect under Win; security concerns.  Under OS/2 I 
>can get the phone to dial using AT&T or iLink/2 dialers.  What I would 
>like to do is connect thru Cingular like I am doing under Win.  Any 
>suggestions on an application and how I can get the information that app 
>would need to be accepted by Cingular.  I have not called Cingular yet 
>because I assume the response will be "what's OS/2", or even "what's 
>IBM".  I have actually gotten the second response from another company.
>
>If I cannot get to the WEB thru Cingular I assume that just leaves 
>subscribing to a dial-up ISP.  I only need this a few weeks per year.  I 
>would rather not pay for a service I hardly use.  I have a free service 
>but it does not seem to stay connected very well.  If that is on purpose 
>I can understand it.  Connection time is not free, someone has to pay 
>for it.
>
>Suggestions?
>
>Ray
>
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